1/m^2(m+4)^1m=8

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Solution for 1/m^2(m+4)^1m=8 equation: 



1/m^2(m+4)^1m=8

We move all terms to the left:

1/m^2(m+4)^1m-(8)=0



Domain of the equation: m^2(m+4)^1m!=0

m∈R



We multiply all the terms by the denominator


-8*m^2(m+4)^1m+1=0

Wy multiply elements

-8m^2(m+1=0

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